How to insert data into xml file from windows form using C#.Net || Insert and Retrieve data from xml file to bind datagridview.

To implement this concept you need to follow the below steps : 

Step1:

On the File menu, click New Project. Select Windows Forms Application as your project type.

Design the Form using controls from Toolbox.

Step2:

Now open the Form.cs page and write the following source code.

Form1.cs Code :

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Windows.Forms;

using System.Xml;

namespace save_data_to_xml

{

    public partial class Form1 : Form

    {

        public Form1()

        {

            InitializeComponent();

        }

        private void button2_Click(object sender, EventArgs e)

        {

            string PATH = "xmldata.xml";

            XmlDocument doc = new XmlDocument();

            //If there is no current file, then create a new one

            if (!System.IO.File.Exists(PATH))

            {

                //Create neccessary nodes

                XmlDeclaration declaration = doc.CreateXmlDeclaration("1.0", "UTF-8", "yes");

                XmlComment comment = doc.CreateComment("This is an XML Generated File");

                XmlElement root = doc.CreateElement("Persons");

                XmlElement person = doc.CreateElement("Person");

                XmlAttribute Name = doc.CreateAttribute("Name");

                XmlElement Designation = doc.CreateElement("Designation");

                XmlElement Location = doc.CreateElement("Location");

                //Add the values for each nodes

                Name.Value = txtName.Text;

                Designation.InnerText = txtDesignation.Text;

                Location.InnerText = txtLocation.Text;

                //Construct the document

                doc.AppendChild(declaration);

                doc.AppendChild(comment);

                doc.AppendChild(root);

                root.AppendChild(person);

                person.Attributes.Append(Name);

                person.AppendChild(Designation);

                person.AppendChild(Location);

                doc.Save(PATH);

            }

            else //If there is already a file

            {

                //Load the XML File

                doc.Load(PATH);

                //Get the root element

                XmlElement root = doc.DocumentElement;

                XmlElement person = doc.CreateElement("Person");

                XmlAttribute Name = doc.CreateAttribute("Name");

                XmlElement Designation = doc.CreateElement("Designation");

                XmlElement Location = doc.CreateElement("Location");

                //Add the values for each nodes

                Name.Value = txtName.Text;

                Designation.InnerText = txtDesignation.Text;

                Location.InnerText = txtLocation.Text;

                //Construct the Person element

                person.Attributes.Append(Name);

                person.AppendChild(Designation);

                person.AppendChild(Location);

                //Add the New person element to the end of the root element

                root.AppendChild(person);

                //Save the document

                doc.Save(PATH);

            }

            //Show confirmation message

            MessageBox.Show("Details have been added to the XML File.");

            //Reset text fields for new input

            txtName.Text = String.Empty;

            txtDesignation.Text = String.Empty;

            txtLocation.Text = String.Empty;

        }

        private void btnview_Click(object sender, EventArgs e)

        {

            try

            {

                XmlReader xmlFile;

                xmlFile = XmlReader.Create("xmldata.xml", new XmlReaderSettings());

                DataSet ds = new DataSet();

                ds.ReadXml(xmlFile);

                dataGridView1.DataSource = ds.Tables[0];

            }

            catch (Exception ex)

            {

                MessageBox.Show(ex.ToString());

            }

        }

    }

}

Step3:
Now build the Solution and Debug it for the output.

Output :

Xml Output file :

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>

<!--This is an XML Generated File-->

<Persons>

  <Person Name="sridhar">

    <Designation>developer</Designation>

    <Location>hyderabad</Location>

  </Person>

<Person Name="karthik">

    <Designation>snr devoloper</Designation>

    <Location>Ameerpet</Location>

  </Person>

</Persons>